How is this done?
2007-10-25 00:13:44 · 5 answers · asked by RogerDodger 1 in Science & Mathematics ➔ Mathematics
It might help if we take get rid of the denominator.
∫[1/(x^5)] dx = ∫[x^(-5)] dx = (-1/4)x^(-4) + C
= -1 / (4x^4) + C
2007-10-25 00:20:20 · answer #1 · answered by Northstar 7 · 1⤊ 0⤋
â«1/(x^5) dx
bring the variable up, doing this the sign of the power will become the opposite:
=â«(x^-5) dx
=(-1/4)(x^-4)+C
bring back the power down.
=-1/(4x^-4))+C
2007-10-25 07:21:54 · answer #2 · answered by benjun s 2 · 1⤊ 0⤋
This is using the power formula of integration
= -(1/4)(x^-5+1) + c
= -(1/4)(x^-4) + c
= -1/(4x^4) + c
2007-10-25 07:28:14 · answer #3 · answered by Synchronizers 3 · 0⤊ 0⤋
1 / x^5 = x^-5
â«x^-5 dx = -1/4 x^-4 + c = -1 / 4x^4 + c
Hope this helps...Doctor Q
2007-10-25 07:18:04 · answer #4 · answered by Doctor Q 6 · 0⤊ 2⤋
-4x^(-4) + C
2007-10-25 07:20:31 · answer #5 · answered by Ivan D 5 · 0⤊ 1⤋