N is a natural number between 10 and 1000. If 6P+4S=4N how many N can be found? P , S indicated in details.?

Question

P is the product of the digits and S the sum of the digits in N.If the natural number N is of the form XYZ where X is the number of hundreds, Y the number of tens and Z the units in N then
P= (X)*(Y)*(Z) ; S = (X)+(Y)+(Z). How many values N can take if 6P+4S=4N

Answer 1

16, 26, 36, 46, 56, 66, 76, 86, 96, 889, 998.
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