Chemisty hw question???? Finding mass of Alumium hydroxide?

Question

What mass of solid aluminum hydroxide can be produced when 50.0mL of 0.200 Molarity Al(NO3)3 is added to 200.0 mL of 0.100 Molarity KOH?

Answer 1

Best to determine as moles first ,then convert to grams later.

First find the balanced equation:

Al(NO3)3 + 3 NaOH ---> Al(OH)3 + 3 NaNO3

Now, find the limiting reagent (if any):

Moles Al+3 = 0.050l x 0.200M = 0.0100mole
Moles OH- = 0.200l x 0.100M = 0.0200mole

OH- will run out first, because, from the balanced equation, we need 3 OH-'s for each Al+3.

From the balanced equation, we can see that we will make:

0.0200moleOH-/3 OH-perAl(OH)3 = 0.00667mole or;

0.00667mole x [(26.98 + 3 x (16 + 1.008)]g/mol = 0.520g of

Al(OH)3

Answer 2

200g