5/x is 5 over x
2007-10-24 17:19:15 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
multiply both sides by x to get rid of the fraction
6x^2 - 7x = 5
6x^2 - 7x - 5=0
Then factor from there
2007-10-24 17:22:33 · answer #1 · answered by Ms. Exxclusive 5 · 0⤊ 0⤋
First, in simple terms ingredient out an x: x(6x^2+27x-one 0 five) you are able to now pull out a three: x(3(2x^2+9x-35)) x(3(2x^2+14x-5x-35) x(3((2x(x+7)-5(x+7)) So our very final product: x(3(2x-5)(x+7)) Have a advantageous day :)
2016-12-18 16:43:43 · answer #2 · answered by ? 4 · 0⤊ 0⤋
6x - 7 = (5/x)
6x^2 - 7x = 5
6x^2 - 7x - 5 = 0
(2x + 1)(3x - 5)
2007-10-24 17:24:49 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
6x-5/x-7=0
6x^2-7x -5=0
a=6
b=-7
c=-5
x1=-1/2
x2=5/3
2007-10-24 17:23:16 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋
6x-7=5/x
6x^2-7x=5
6x^2-7x-5=0
(3x-5)(2x+1)=0
x=-0.5,(5/3)
2007-10-24 17:24:00 · answer #5 · answered by Anonymous · 0⤊ 0⤋