2007-10-24 16:51:28 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Common factor is 2x - 3
(2x - 3)(5x + 7)
2007-10-26 06:19:21 · answer #1 · answered by Como 7 · 1⤊ 0⤋
Group Factoring
(5x + 7)(2x - 3)
2007-10-24 17:35:13 · answer #2 · answered by Sherman81 6 · 0⤊ 1⤋
you add the 5x from the first term with the 7 from the second term, and multiply it by (2x-3) so it will look like:
(5x+7)(2x-3)
2007-10-24 16:55:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋
It's :
(5 x + 7)(2 x - 3).
This is found as follows ---
Since (2 x - 3) is common to both terms, you can simply COMBINE the two separate factors of that common expression (2 x - 3), that is both (+) 5 x and + 7, into another factor, namely (5 x + 7).
That then yields:
(5 x + 7)(2 x - 3)
as the final factorization.
QED
Live long and prosper.
2007-10-24 16:54:30 · answer #4 · answered by Dr Spock 6 · 0⤊ 0⤋
5x(2x-3)+7(2x-3)
Use distributive property. Distribute the term outside the parentheses to those inside:
10x^2 - 15x + 14x -21
combine similar terms
10x^2 - x - 21
(5x + 7) (2x - 3)
2007-10-24 16:58:27 · answer #5 · answered by edith p 3 · 0⤊ 1⤋
Qn: 5x(2x-3)+7(2x-3)
The common factor in this qn is (2x-3)
If we take out (2x-3), we are left with
(2x-3)(5x+7)
2007-10-24 16:55:33 · answer #6 · answered by Anonymous · 0⤊ 0⤋
instead of multiplying (2x-3) by 5x and then separately by 7 as is written originally, just multiply 5x and 7 in one paranthesis, as (5x+7)(2x-3)
you can tell that their the same because (5x+7)(2x-3) equals 10xsquared +4x-21, which is the same thing you get when you multiply 5x(2x-3)+7(2x-3)
2007-10-24 17:14:03 · answer #7 · answered by Trevor 2 · 0⤊ 1⤋
take out a (2x-3)
(2x-3) (5x+7)
2007-10-24 16:54:20 · answer #8 · answered by Anonymous · 0⤊ 0⤋