What minimum speed must you give the pail at the highest point of the circle if no water is to spill from it?
2007-10-24 15:56:00 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
F = v^2 / R
= ma
=> Velocity = squareoot (mass of bucket and water * 9.81 m/s^2 / .700 meters)
I dont know if this is right
2007-10-24 16:00:22 · answer #1 · answered by Anonymous · 0⤊ 2⤋
The equation for centripetal force (Fc) is actually Fc=m x (v^2/r). What this means is that if the radius would increase, then subsequently in order for the centripetal force to stay the same then the velocity for the longer armed man would have to increase in order to compensate for the larger radius that it is being divided by.
2016-04-10 03:46:05 · answer #2 · answered by Anonymous · 0⤊ 0⤋
the rotational acceleration must be equal to or greater than gravitational acceleration. Im trying to remember the equation but i believe its something like v = r * omega
v is rotational velocity
r is radius
omega is rotational acceleration. make sure you convert to and from radians
2007-10-24 16:03:47 · answer #3 · answered by Jamie G 2 · 0⤊ 0⤋
You need to (over)balance the gravitational force of Mg with
M(1/R)(V**2) so R(9.8 m/sec**2) = V**2
V=Sqrt ( 0.7m) ( 9.8 m / sec **2) = Sqrt (6.86 m**2/sec**2) =
2.62 m/sec
2007-10-24 16:15:37 · answer #4 · answered by LucaPacioli1492 7 · 1⤊ 0⤋
a= v^2/r
but youd need the acceleration
2007-10-24 18:01:31 · answer #5 · answered by Anonymous · 0⤊ 0⤋