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Two concentric circles are given. A tangent to the inner circle forms a chord twelve inches long in the larger circle.

2007-10-24 15:37:27 · 1 answers · asked by Albert J 1 in Science & Mathematics Mathematics

1 answers

Say the radius of the larger circle is R and that of the smaller one, r. Draw a perpendicular from the center of the circles to the tangent point and from the center to the point the tangent intersects the larger circle.

You will see that there is a right triangle with one leg r, the other 6 inches and the hypotenuse R.
r**2 + 36 = R**2. This gives 36=R**2 - r**2
But the area required is Pi (R**2 - r**2) = 36 Pi

2007-10-24 15:51:23 · answer #1 · answered by LucaPacioli1492 7 · 1 0

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