Can someone explain how to solve this problem in detail?
77=9/5x+32
Any help would be appreciated.
2007-10-24 15:21:12 · 4 answers · asked by shexlovesxdancin 1 in Science & Mathematics ➔ Mathematics
77 = 9/5x + 32
77 - 32 = 9/5x
45 = 9/5x
x = 45 * 5/9
x = 25
2007-10-24 15:25:01 · answer #1 · answered by MARS 3 · 0⤊ 0⤋
77=9/5x+32
First distribute like terms:
9/5x = 77 - 32, or 45
Divide both sides by 9:
1/5x = 5
Multiply both sides by x:
1/5 = 5x
Divide by 5:
x = 1/25
2007-10-24 15:28:58 · answer #2 · answered by Robert S 7 · 0⤊ 0⤋
77 = (9/5)x + 32
Solve for x by getting it on one side of the equation
1) Subtract 32 from both sides
45 = (9/5)x
2) Divide by (9/5) {To get x by itself}
It might help to turn 9/5 into a decimal to do this if you have a standard calculator and not a graphing calc or one capable of fractions
45/(9/5) = x
25 = x
x=25
Plug and chug and you will see it works out
Hope this helps
2007-10-24 15:28:37 · answer #3 · answered by Jessie James 2 · 0⤊ 0⤋
The first thing to do is subtract 32 from both sides to get the variable alone
45 = 9/5x
Multiply both sides by 5/9 to get rid of the fraction with the variable
45(5/9) = x
25 =x
2007-10-24 15:29:00 · answer #4 · answered by Ms. Exxclusive 5 · 0⤊ 0⤋