O no please help?

Question

Factor and Reduce
(4x^4 – 8x^3 – 60x^2) / (4x^4 – 100x^2)
thankyou

Answer 1

First each term is divisible by 4x^2, so factor that out:
((4x^2)(x^2 - 2x - 15))/((4x^2)(x^2 - 25))

The 4x^2 factor will cancel out since its in numerator & denominator, so we have:
(x^2 - 2x - 15)/(x^2 - 25)

Next, factor the quadratic expressions in numerator & denominator to get:
((x + 3)(x - 5))/((x + 5)(x - 5))

Since numerator & denominator both have (x-5) factors, those cancel each other, leaving:
(x + 3)/(x + 5) *Your Final Answer!!*

Answer 2

Its greatest common factor (GCF).
It's 4x^(x^2-2x-15)/4x^(x^2-25).
Cross out the two 4x^'s.
Factor x^2-25 into difference of perfect squares, which equals (x+5)(x-5). And x^-2x-15 is factored into a trinomial, which equals (x-5)(x+3).

Now you're equation is
(x-5)(x+3) over
(x-5)(x+5)
Cross out the two (x-5)'s
Answer is (x+3)/(x+5) or
(x+3) over
(x+5)

Answer 3

first pull out 4x^2 from top and bottom

(4x^2)(x^2 - 2x - 15) / (4x^2)(x^2 - 25) - now cancel out 4x^2

(x^2 - 2x - 15) / (x^2 - 25) now factor out top and bottom

(x - 5)(x +3) / (x-5)(x+5) and cancel out like terms

(x+3)/(x-5)

Answer 4

4x^2(x^2-2x-15)/4x^2(x+5)(x-5) = (x-5)(x+3)/(x+5)(x-5)=
(x+3)/(x+5)

Answer 5

I need help myself wish i could help