Its all in how you define your coordinate system. If you use the most common one, +ve x to the right and +ve y up, then
Say you're moving in the -ve x direction. (To the left) but your speed is getting faster. Your acceleration is still negative.
The converse is true when you are slowing down in the -ve direction. You have a positive acceleration.
2007-10-24 13:19:16
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answer #1
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answered by Anonymous
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turning. An object's tangential velocity could either be constant, slowing down or speeding up. But if there is a change in the direction of motion, there is an acceleration in the direction of the radius of curvature of the change in velocity. Changing direction is always considered a positive acceleration one way or the other.
2007-10-24 20:27:24
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answer #2
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answered by Kevin 5
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the only way that can happen is if your traveling in a -ve direction. So set up a coordinate system and say that your going left (negative) then say you accelerate to the right (+ve). That way you slow down in the negative direction.
Just reverse this for the other case
2007-10-24 20:20:50
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answer #3
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answered by james m 3
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we are talking about that in IPC but when you accelerate can have a negative accelartaion but the object has to slow down.... NOT SPEED UP... ( that question was on my test today) so like ya..
2007-10-24 20:21:28
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answer #4
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answered by Anonymous
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v=@t+vo so if vo is negative(remember velocity is a vector)
v can be negative
@=4m/s^2 and vo=-20m/s
The initial speed is 20m/s and at t=5s the speed is 0
2) @=-4m/s^2 (acceleration is also a vector) and vo=-20m/s
v=-4t-20
at t= 0 the speed is 20m/s and at t=5s the speed is 40m/s
2007-10-24 20:25:46
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answer #5
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answered by santmann2002 7
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isnt that impossible?!
how can a positive be a negative...
so that means its getting faster but its also decelerating at the same time?
umm..ok, i was like of no use but could the answer be
it cant? [=
2007-10-24 20:18:30
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answer #6
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answered by muzicggirl 3
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It's all relative to your reference point.
2007-10-24 20:29:03
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answer #7
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answered by pblcbox 4
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