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We know that P(A) = 0.4, P(B) = 0.1, and P(A ∪ B) = 0.5.

Therefore, P(A ∩ B) =

2007-10-24 12:49:12 · 2 answers · asked by gonzo_fan2007 2 in Science & Mathematics Mathematics

2 answers

P(A^B) = P(A)+ P(B) - P(AUB)
Applying that here:
Answer is 0.4 + 0.1 - 0.5 = 0.0

2007-10-24 12:53:29 · answer #1 · answered by That's me ... 3 · 0 0

We know that P(A∪B) + P(A∩B) = P(A) + P(B), so P(A∩B) = P(A) + P(B) - P(A∪B) = .4 + .1 - .5 = 0. So A and B are mutually exclusive events.

2007-10-24 19:55:12 · answer #2 · answered by Pascal 7 · 0 0

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