your equation is in the form f(x)=ax^2+bx+c
that means, a=-4, b=-6, c=2.
Now plug that into the quadratic formula.
I got x= -3/2 and x=1/2
2007-10-24 12:52:47
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answer #1
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answered by Anonymous
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http://answers.yahoo.com/question/index;_ylt=Au3lMz2q_67k5hD_Op.cVyXsy6IX;_ylv=3?qid=20071024155050AAQSVMo
ya
2007-10-24 12:50:19
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answer #2
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answered by Anonymous
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First, take out the common factor and the minus. The expression becomes : f(x) = -2(2x^2 + 3x - 2) Much easier to solve now, go do it.
Well try f(x) = -2(2x - 1) (x + 2)
For f(x) to = 0 x must = 1/2 or -2 (if my workings are right)
Expand my factors and see if you come out with the original equation.
2007-10-24 12:54:30
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answer #3
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answered by bullswool888 5
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Standard form of a quadratic is
f(x)=ax^2+bx+c
so in our case
a=-4
b=-6
c=2
The quadratic formula is
x=(-b+/-sqrt(b^2-4ac))/(2a)
plug in values for a, b, and c.
x=(-(-6)+/-sqrt((-6)^2-4(-4)(2)))/(2(-4))
x=(6+/-sqrt(36-32))/(-8)
x=6+/-sqrt(4)/(-8)
x=(6+/-2)/(-8)
x=(6+2)/(-8) and x=(6-2)/(-8)
x=8/(-8) x=4/(-8)
x=-1 x=-1/2
2007-10-24 12:59:58
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answer #4
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answered by mathman 3
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quadratic formula= -b(pos/neg) squareroot of (b^2-4ac) divided by 2(a)
so, using the formula,
-(-6)(pos/neg)squareroot of ((-6)^2-4(-4*2)
divided by 2(-4)
leaving
6(pos/neg)squarerootof(68) divided by -8
68div 4 =17, right?
so we can replace
6(pos/neg) squareroot of(17*4) div by -8
resulting to
6(pos/neg) 2 squareroot of 17
div -8
.
taking the positive part,
x= - (6+2sqr17)/8
taking the negative part,
x= - (6-2sqr17)/8
i hope that helps. good luck!
2007-10-24 12:59:50
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answer #5
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answered by Anonymous
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-b+-sqrt(b^2-4ac) quadratic equation
6+or-sqrt(36-4(-4)(2))/-8 numbers plugged in
6+-2sqrt(17)/-8 simplify
3+-sqrt(17)/-4 simplified again
Zeros: 3+sqrt(17)/-4
3-sqrt(17)/-4
2007-10-24 12:55:24
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answer #6
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answered by jacob D 3
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f(x)= -2(2x^2 + 3x -1)
for f(x) to =0 then
2x^2 +3x-1 must =0
and
2x^2+3x equals 1
dividing both sides by x
2x +3 equals 1/x
2x-1/x equals -3
2007-10-24 13:07:14
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answer #7
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answered by Anonymous
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f(x) = -4x^2-6x+2
x = [6 +/- sqrt( 6^2 -4(-4)(2))]/(2(-4))
x = [6 +/- sqrt (68)]/-8
x = [6 +/- 2sqrt(17)]/-8
x = [3 +/- sqrt(17)]/-4
2007-10-24 12:58:11
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answer #8
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answered by ironduke8159 7
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x=(-b(+or-)(b^2 - 4ac)^0.5)/2a
here a=-4
b=-6
c=2
x=6(+or-)(36+32)/-8
x=(6+68)/-8 = -9.25
or x= (6-68)/-8= 7.75
2007-10-24 12:53:59
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answer #9
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answered by Stef W 2
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