Can someone explain grade 9 algebra?

Question

Like can you go through these please?

5(2x-3) = 2(3x+7)+11

3(5y+4) = 5(2y-3)+22

3+5-3m = -2m+m-1

Answer 1

You havd to distribute it, meaning that if you can't combine the terms in the parenthesis, you take the number outisde the parenthesis and multiply it with those that are.

5(2x-3)=2(3x+7)+11
10x-15=6x+14+11
10x-15=6x+25
10x=6x+40
4x=40
x=10

Answer 2

5(2x-3) = 2(3x+7) + 11 First do distributive property's.
10x - 15 = 6x + 14 + 11 Then combine like terms
10x - 15 = 6x + 25 Now minus 6x to both sides and Add 15 to both sides
4x = 40 Now time to divide 30 by 4
x = 10

3(5y + 4) = 5(2y - 3) + 22 First do distributive Property's
15y + 12 = 10y - 15 + 22 Then Combine like terms
15y + 12 = 10y + 7 Now minus 7 to both sides and minus 15y to both sides
5 = 5y Now divide 5 to both sides
1 = y or y = 1

3 + 5 - 3m = -2m + m - 1 First combine like terms
8 - 3m = -m - 1 Now Add m to both sides and minus 8 to both sides
- 2m = -7
m = 3.5

It is very easy when you get it.

Answer 3

5(2x-3) = 2(3x+7)+11
First remove brackets by multiplying:
10x - 15 = 6x + 14 + 11
Then collect like terms on opposite sides:
10x - 6x = 15 + 14 + 11
Simplify like terms:
4x = 40
Divide both sides by 4:
x = 10


3(5y+4) = 5(2y-3)+22
15y + 12 = 10y - 15 + 22
15y -10y = 22 - 15 -12
5y = -5
y = -1

3+5-3m = -2m+m-

Answer 4

For the first problem you first have to distribute. That means that 5(2x-3) is 10x-15, and 2(3x+7) is 6x+14.

So instead of having 5(2x-3)=2(3x+7)+11 you will have a simpler problem saying 10x-15=6x+14+11.

6x+14+11 is the same as 6x+25 too, so now you have a very simple problem. 10x-15=6x+25. What you want to do for all types of math problems like these is getting the variable (x) on one side of the equation. To do this you could either subtract 10x from each side of the equation or 6x. I will subtract 6x so that you can have x be positive.

10x-6x=4x, and 6x-6x=0. For these problems you must remember that one thing you do to one side always happens to the other side, so after subtracting 6x from both sides you now have 4x-15=25.

Do the same thing as I showed you with the x. Try to get a number on one side of the equation. Right now you have -15 on one side and 25 on the other. You want only one number on one side, so you add 15 to both sides. This is because -15 is on one side.

After adding 15 to both sides you know have the equation 4x=40. Now all you have to do now is simple divide both sides by 4 and your final answer is x=10.

I am not going to answer the other two because they use are the same types of problems as the first one. Sorry if I was confusing, but I know you will figure it out.

Answer 5

You can trust my answers, i took algebra last year already, so i already know these are right.

1. 5(2x-3)=2(3x+7)+11
10x-15=6x+14+11
10x-15=6x+25
4x=40
x=10

2.15y+12=10y-15+22
5y=10
y=2

3.3+5-3m=-2m+m-1
8-3m=-1m-1
9=2m
m=4.5

Answer 6

10x-15=6x+14+11
4x=40
x=10

15y+12=10y-15+22
5y= -6
y= -6/5

-2m=-9
m=9/2