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f(x)= x^2 -2x +1

g(x)=x^2 +2x +1

c=5

2007-10-24 12:34:59 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

First find (fog)(x) [plug g(x) into all the x's in f(x)]:
f(g(x)) = (x^2 + 2x + 1)^2 - 2(x^2 + 2x + 1) + 1

Plug in 5 for x:
f(g(5))
= (5^2 + 2*5 + 1)^2 - 2(5^2 + 2*5 + 1) + 1
= (25 + 10 + 1)^2 - 2(25 + 10 + 1) + 1
= (36)^2 - 2(36) + 1
= 1225

2007-10-24 12:40:33 · answer #1 · answered by whitesox09 7 · 0 0

g will be the function that 'fits' inside of the x's in the f(x) function:

(x^2 -2x +1)^2 -2( x^2 -2x +1) +1
and just plug in 5

2007-10-24 12:39:38 · answer #2 · answered by pari 3 · 1 0

f(g(5))

g(5) = 25 + 10 + 1 = 36

f(36) = 1225

2007-10-24 12:39:12 · answer #3 · answered by Axis Flip 3 · 1 0

Well, let's make our lives a little easier: Note that f(x) = (x-1)² and g(x) = (x+1)². Then we have:

(f∘g)(5) = f(g(5)) = f((5+1)²) = f(36) = (36-1)² = 1,225

2007-10-24 12:39:25 · answer #4 · answered by Pascal 7 · 1 0

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