In an equilateral triangle with both an inscribed and a circumscribed circle, if the area of the larger of these two circles is 60, what is the area of the smaller?
2007-10-24 12:13:55 · 2 answers · asked by Ti-Mon 2 in Science & Mathematics ➔ Mathematics
The radio of the circumscribed circle = r=sqrt(60/pi)
and the radius of the inscribed circle is 1/2 r and its area
= pi*r^2/4 = 15
2007-10-24 14:05:18 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋
Draw the line as stated. DC is a million/4 of the full length, FG is a million/32, FD is a million/sixteen. you will discover that H is 5/8 of how from A to B, so... GH = a million/32 + a million/sixteen + a million/4 + a million/8 of the full length. you in addition to might comprehend that DC = a million/4 = sixteen, so... (a million/8)*sixteen + (a million/4)*sixteen + sixteen + (a million/2)*sixteen = 30.
2016-10-04 12:40:44 · answer #2 · answered by missildine 4 · 0⤊ 0⤋