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how do i simplify 54 inside a radical sign, but not square rooted, like, cube rooted? i dont exactly know how to put it, but there's a little 3 outside of a radical sign containing 54

2007-10-24 11:29:25 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

Start by factoring the number:
54 = 2 * 3 * 3 * 3

Notice how you have 3 appearing three times, so you can pull that outside the cube root symbol.

³√54
= ³√(27 * 2)
= ³√27 * ³√2
= 3 ³√2

There's your answer.

2007-10-24 11:32:37 · answer #1 · answered by Puzzling 7 · 0 0

so if the question is asking for the cube root of 54 we will have to see the prime factorization
2 x 3 x 3 x 3 = 54
since there are three 3's in the prime factorization we can take the three out and write it as three times the cube root of three(the same sign on the 54)

2007-10-24 18:33:57 · answer #2 · answered by pt_of_vu 2 · 0 0

³√54
= ³√(27 X 2)
= 3 ³√2

2007-10-24 18:34:01 · answer #3 · answered by harry m 6 · 0 0

its 54 cube rooted... so you have to factor 54 which gives you 2*3^3... only the 3 can come out of the cube root... because it has enough exponential power to match the cube root's requirement... so you will have
3cuberoot of 2

2007-10-24 18:34:36 · answer #4 · answered by Allen C 3 · 0 0

Without a calculator it is very difficult but you solve it like you would if you had to square root it, by the way the answer is approxiamately 3.7797631496846194943016318218347

2007-10-24 18:36:33 · answer #5 · answered by nexxnokk 1 · 0 0

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