What is the integral of e^(1/x)/x^2 ?

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What is the integral of e^(1/x)/x^2 ?

What is the integral of e^(1/x)/x^2 ?

Please do it step by step

2007-10-24 11:01:02 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

2 answers

Just observe that 1/x^2 is the derivative of - 1/x. So, we have an integral of the type

Int -e^u du = - e^u + C. Since u = 1/x, it follows

integral of e^(1/x)/x^2 = - e^(1/x) + C

2007-10-24 11:15:07 · answer #1 · answered by Steiner 7 · 6⤊ 0⤋

-e^(1/x) + c, since [-e^(1/x)]' = e^(1/x)/x^2

2007-10-24 11:05:18 · answer #2 · answered by sahsjing 7 · 1⤊ 0⤋