A solution is prepared by adding 44.0 mL of 0.060 M HCl to 152.0 mL of 0.30 M HNO3. Calculate the concentratio

Question

[H+]=??
[OH -]=??
[Cl -]=??
[NO3-]=??

Answer 1

The total volume is 44.0 + 152.0 = 196.0 (ml)
[H+] = (44.0*0.060 + 152.0*0.30)/196.0 = 0.25M
[OH -] = 10^-14/0.25 = 4x10^-14 M
[Cl -] = 44.0*0.060/196.0 = 0.013M
[NO3-] = 152.0*0.30/196.0 = 0.23M

Answer 2

the steps leading to the solution is right in the above answer. but the calculation is wrong.
[H+]= .17M
[OH -]= 5.9 x 10^-14M
[Cl -]= .013M
[NO3-]= .16M