Algebra 1 Help!?

Question

In our book we have to write an exspression for each of the following

9.the sum of an even interger and two times the next even interger

10. the sum of 1/4 of an interger, 1/5 of the next interger, adn 1/2 of the following interger.


Please Help Thanks

Answer 1

Question 9
Sum = 2n + 2(2n + 2)
Sum = 2n + 2n + 4
Sum = 4n + 4

Question 10
Sum = n/4 + (n + 1)/5 + (n + 2)/2
Sum = 5n/20 + 4(n + 1) / 20 + 10(n + 2) / 20
Sum = (19n + 24 ) / 20

Answer 2

9. Let the even integer be 2x. {2x because it has to be even}

The next even integer is 2x + 2, so

two times this is 2(2x + 2) = 4x + 4.

The sum is 2x + 4x + 4 = 6x + 4

10.Let x be the lowest integer. The next one is (x + 1), and the next is (x + 2)

So you have to add; x/4, (x + 1)/5 and (x + 2)/2

= x/4 + (x + 1)/5 + (x + 2)/2.

This is the expression. I assume that this is the answer that you need.

Answer 3

9. x+ (x+2)
10. X/4 +(X+1)/5+(X+2)/2

Answer 4

9. If you start with an even integer, you have to add 2 to get to the next even integer (an integer is a whole number ... in other words it doesn't have any numbers after the decimal point). I'll call the first even integer x.
x + 2*(x+2) is the answer
2*(x+2) is 2*(next even integer)

10. "next integer" just means the first number +1. I'll call the first integer x as well
(1/4)*x + (1/5)*(x+1) + (1/2)*(x+2)