If i have a metal sphere and I need to calculate the height it must fall from, I know the weight of the sphere, this radius (I have the sphere) air resistance doesn't matter and it will be falling under the earth's gravity (I don't quite have the money to pop into space)
10 points for best answer
2007-10-24 05:45:40 · 2 answers · asked by prof. Jack 3 in Science & Mathematics ➔ Physics
Any dense object will fall at the same rate i.e. g = 9.8 m/s².
The distance of freefall is H = ½gt²
The impact velocity is v = gt
where t is time.
2007-10-24 05:51:50 · answer #1 · answered by gebobs 6 · 0⤊ 0⤋
there is not any Anti gravity chamber that exists on earth! yet I honestly have experienced both different strategies that the Astronauts practice. In Huston Texas they have a huge pool that would in good structure a a million:a million scale modle of componants of the international area station the position the Astronauts bypass in totally perfect up and flow there practising their walks. any incorrect way is on a airplane that they have got nick named "The Vomit Comit" the position they could simulate "0 Gravity" by diving the airplane and making you bypass right into a state it truly is elementary as "loose fall" Esentually although there is not any such element as 0 gravity because no matter how minute, you could in no way ruin out gravity. Even in orbit you're not to any extent further in "0 Gravity" you're honestly in a state of loose fall consistently falling in the direction of the earth.
2016-10-22 22:40:10 · answer #2 · answered by ? 4 · 0⤊ 0⤋