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At a specific set of conditions, 246.6 kJ is given off when 1 mol H2O(g) forms from its elements. Under the same conditions, 283.6 kJ is given off when 1 mol H2O(l) forms from its elements. Calculate the heat of vaporization of water at these conditions.
kJ

2007-10-24 04:58:07 · 2 answers · asked by Dumb B 1 in Science & Mathematics Chemistry

2 answers

246.6 kJ is given off when 1 mol H2O(g) forms from its elements, it really does not matter if H2O(l) is formed first, then vaporize the second. Therefore, the heat of vaporization of water at these conditions is simply the difference of 283.6 kJ and 246.6 kJ.

2007-10-24 20:19:03 · answer #1 · answered by Hahaha 7 · 0 0

you need to verify the expenditures so: Gallium has a three+ can charge, and oxygen has a 2- can charge so Gallium oxide could be Ga2O3 so the molecule is impartial. Calcium has a 2+ can charge and the polyatomic Sulfate has a 2- can charge so Calcium sulfate could be, CaSO4.

2016-10-04 12:04:11 · answer #2 · answered by ? 4 · 0 0

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