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2007-10-24 03:41:55 · 3 answers · asked by Math_question 2 in Science & Mathematics Mathematics

3 answers

Let's look for rational zeros first.
Any such factor must be an integer dividing 4
and after some trial we find 2 is a zero,
since 2^3 -4-4 = 0
So x-2 is a factor. By synthetic division or long division,
we find that the quotient is x²+2x+2.
So
x^3 - 2x -4 = (x-2)(x²+2x+2).

2007-10-24 03:53:35 · answer #1 · answered by steiner1745 7 · 1 0

(x-2)(x^2 + 2x +2)

cube of a trinomial =)

2007-10-24 10:50:28 · answer #2 · answered by theresagarfield 3 · 0 1

(x-2)(x^2 + 2x +2)

2007-10-24 10:49:01 · answer #3 · answered by HT 2 · 0 1

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