How do you solve this alggebra problem? It has me confused.
5-2(x+3)=x-3(x+1)
2007-10-24 02:14:18 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Hi Andrew,
For this question you first need to distribute the -2 and -3 over the respective factors on both sides of the equation to get:
5 - 2x - 6 = x - 3x - 3
Next, simplify both sides of the equation by combining "like" terms to get:
-1 - 2x = -2x - 3
Next, add 2x to both sides of the equation. Once you do this, you'll notice there's a surprise in store for the answer:
-1 = 0x - 3
However, at this point, you see that we have 0x and anything times 0 is just 0. Therefore, we get -1 = -3 which is obviously not true. This therefore, means that there's no solution!
FINAL ANSWER: NO SOLUTION
=)
I hope that helps you out! Please let me know if you have any other questions!
Sincerely,
Andrew
2007-10-24 02:59:13 · answer #1 · answered by The VC 06 7 · 0⤊ 0⤋
5 - 2(x + 3) = x - 3(x + 1)
=> 5 - 2x -6 = x - 3x -3
=> - 2x -1 = - 2x - 3
There is realy something wrong with the question
i think it is 5- 2(x+3) = x^2 -3(3+1)
2007-10-24 09:28:54 · answer #2 · answered by Anonymous · 0⤊ 1⤋
5-2(x+3)=x-3(x+1)
This is a lot like the previous one you posted.
1) distribute the number through the parentheses
2) combine like terms where possible
3) get all the x on one side and all the numbers on the other
4) get x by itself
5 - 2(x + 3)=x - 3(x + 1)
5 - 2x - 2(3) = x - 3x - 3(1)
5 - 2x - 6 = x - 3x - 3
-2x - 1 = -2x - 3
-2x - 1 + 1 = -2x - 3 + 1
-2x = -2x - 2
-2x + 2x = -2x - 2 + 2x
0 = -2
This means that equation has NO SOLUTION.
2007-10-24 09:22:38 · answer #3 · answered by Mathematica 7 · 2⤊ 1⤋
5-2(x+3)=x-3(x+1)
5-2x+6 = x - 3x+1
1-2x = 1-2x
there 2x - 2x = 0
there fore x = 0
:)
2007-10-24 09:20:07 · answer #4 · answered by bipinvkadam 2 · 0⤊ 2⤋
I think it is x=9, but is so long ago I may be wrong (I probably am)
LoL
2007-10-24 20:56:02 · answer #5 · answered by Anonymous · 0⤊ 0⤋
i will solve it this way
5-2x-6=x-3x-3
-2x-1=-2x-3
since -2x will get canceld this equation has no roots
2007-10-24 09:20:41 · answer #6 · answered by Anonymous · 0⤊ 2⤋
5-2x-6=x-3x-3
-2x-1=-2x-3
0=-2
no solution
2007-10-24 09:19:03 · answer #7 · answered by norlan o 2 · 0⤊ 2⤋
5 -2x-6=x-3x-1
-1-2x=-2x-1
x=0
Let me know if I need to explain it
2007-10-24 09:18:44 · answer #8 · answered by Dana O 3 · 0⤊ 2⤋
Multiply out the brackets, then make sure you put the variables on one side, then make sure x is on its own.
2007-10-24 09:20:33 · answer #9 · answered by ManicStreetPreacher 2 · 0⤊ 3⤋
so could I !! Just multiply it out, get your variables on one side, and then isolate x.
2007-10-24 09:17:38 · answer #10 · answered by Lord Mavramorn 2 · 0⤊ 2⤋