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If not prove that such a magic square doesn't exists

2007-10-24 00:16:55 · 6 answers · asked by annapoorani_am04 2 in Science & Mathematics Mathematics

Find a 3 by 3 magic square in which all of whose entries are distinct perfect squares? If not prove that it is not possible

2007-10-24 01:12:34 · update #1

6 answers

i dont believe so because the definition of a perfect square. it is an n x n matrix with the numbers 1 to n^2. a three by three perfect square matrix can only use the numbers 1-9.

2007-10-24 01:21:26 · answer #1 · answered by Anonymous · 0 0

I assume that the problem is:

Find a 3x3 matrix of perfect squares, all distinct, and an integer N, such that:

1. Each row adds to N
2. Each column adds to N
3. (Maybe) Each diagonal adds to N

Every square is congruent to either 0 or 1 modulo 4. Therefore, N is congruent to either 0, 1, or 2 modulo 4. We can also assume that at least one of the numbers is odd, because if they were all even we could just divide everything by 4 and have a new magic square with smaller entries.

All that said, I'm not seeing any great way to make progress on the problem. Sorry.

2007-10-24 12:26:28 · answer #2 · answered by Curt Monash 7 · 0 0

Is the Q complete?

2007-10-24 08:01:52 · answer #3 · answered by wizkid_388 2 · 0 0

not possible to my knowledge.but at least 5 can be to your condition

2007-10-24 07:39:54 · answer #4 · answered by karthikthehun 1 · 1 0

tell us how much each row needs to add up to?

2007-10-24 07:40:46 · answer #5 · answered by rrai 3 · 0 1

please clarify.

2007-10-24 07:21:46 · answer #6 · answered by King-Kirby 2 · 0 1

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