1) CCl4
2) HCl
3) H2CO
4) BF4 -
5) NH3
2007-10-23 20:20:18 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
3 is correct: 2 sp2 orbitals bond with the s orbitals of H atoms and one bonds with O along with p-orbital overlap to make up the double bond.
1 and 4 have sp3 hybrid orbitals; 2 and 5 involve p orbitals in the bonding to the s of H.
2007-10-23 20:51:17 · answer #1 · answered by Anonymous · 2⤊ 0⤋
Count the groups attached. If 4 groups, it's sp3 If 3 groups it's sp2 If 2 groups it's sp
2016-04-10 01:43:45 · answer #2 · answered by ? 4 · 0⤊ 0⤋
1. ccl4
c=1s2 2s2 2p2(ground state)
c=1s2 2s1 2px1 2py1 2pz1(excited state)
sp3
4. BF4
B=1s2 2s2 2p1(ground state)
p orbital has 3 sub,sub-shells ie px, py,pz.
B= 1s2 2s1 2px1 2py1 2pz0
sp2
2007-10-23 21:10:13 · answer #3 · answered by saranyal 2 · 0⤊ 0⤋
H2CO 4 BF4-
2007-10-23 21:20:10 · answer #4 · answered by blessing u 1 · 0⤊ 0⤋
3) H2C=O
2007-10-23 20:22:57 · answer #5 · answered by papastolte 6 · 1⤊ 0⤋
H2CO
2007-10-23 22:34:34 · answer #6 · answered by maussy 7 · 0⤊ 0⤋
1,CCl4
2007-10-23 20:33:40 · answer #7 · answered by rHai 2 · 0⤊ 1⤋