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Calculate the force of a 10 kg object that is pushed 44 m by 3 people for 17 minutes, when the object finally touches you its is traveling 3 m/s2. ( Note: it is pushed by 3 people )

2007-10-23 19:28:55 · 3 answers · asked by rockerkid100 2 in Science & Mathematics Physics

3 answers

Do you want the force exerted by each person? Is it assumed that the force is constant throughout hte 17 minutes? Do you mean 3 people all at the same time, or one after the other? Each one pushes for 17 min?

The distance an object moves under constant (force and) acceleration a is s = 0.5*a*t^2; if you know s and t, you can find a:

a = 2*s/t^2 a = 88/(17*60)^2 meter/sec^2 = 8.46*10^-5 m/s^2

Once you have a, the force is given by F = m*a; the force per person (if they are equal and all at the same time) is m*a/3
F = 8.46*10^-4 N

per person = 2.82*10^-4 N

2007-10-23 19:38:19 · answer #1 · answered by gp4rts 7 · 0 0

thank you my friends now next i see

2016-10-25 15:50:36 · answer #2 · answered by arash 1 · 0 0

is this the whole question?

2007-10-23 19:36:26 · answer #3 · answered by acp91 2 · 0 0

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