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Find the coordinates of the image of quadrilateral Q(-6, -1), U(-4, 6), A(0, 7), D(3, 5), after performing a reflection over the line y = x. Show all work using the appropriate reflection matrix.

2007-10-23 18:02:45 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

Hi,

For every point (a,b)-->(b,a)

Q(-6,-1)-->Q'(-1,-6)
U(-4,6)-->U'(6,-4)
A(0,7)-->A'(7,0)
D(3,5)-->D'(5,3)

Multiply the 4x2 QUAD matrix by the 2x2 matrix shown below:

[-6..-1]
[-4...6]..[0..1]
[..0..7]..[1..0]
[..3..5]

This also gives the answers listed above.

I hope that helps!! :-)

2007-10-23 22:21:54 · answer #1 · answered by Pi R Squared 7 · 0 0

Q(-6, -1), U(-4, 6), A(0, 7), D(3, 5)

The result is
Q'(-1,-6), U'( 6,-4), A'(7,0), D'(5,3)

Matrix
-6 -4 0 3
-1 6 7 5

2007-10-23 19:45:18 · answer #2 · answered by iyiogrenci 6 · 0 0

ok, i no for optimistic the the line Y=X looks like / , cuz whilst Y=4 then X=4. same with any variety~~ Y= -2 then X= -2.. anyhow... i'm rather optimistic that u basically change the two. like Q will equivalent -2,7 i think of, yet do now not believe me one hundred%

2017-01-04 08:58:17 · answer #3 · answered by spraggs 3 · 0 0

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