lim as x approaches infinity (+) ...ln [(x^.5) + 5] divided by ln x...i believe it is zero...i may be wrong please help...i need by tomorrow !!
2007-10-23 17:01:54 · 3 answers · asked by Kenichi S 2 in Science & Mathematics ➔ Mathematics
This was asked earlier. See http://answers.yahoo.com/question/index;_ylt=AsurtDix22lMtDR3eoCV5e4Cxgt.;_ylv=3?qid=20071023201639AA2X4cG
2007-10-23 17:26:51 · answer #1 · answered by Ron W 7 · 0⤊ 0⤋
plug in really high numbers for x. like, 1000000, 10000000, 10000000000 and see where it goes...
2007-10-23 17:10:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2] (ln(a million/x))^x=(-ln(x))^x assume that y=(-ln(x))^x . for this reason ln(y)=xln(-ln(x))=(ln(-ln(x))/(a million/x) So, lim ln(y) = lim (ln(-ln(x))/(a million/x)=lim ((-a million/x)/(-lnx))/(-a million/x^2)=lim ((-x)/ln(x))=lim (-a million/(a million/x))=lim (-x)=0 Then y=a million. hence lim(ln(a million/x))^x as x strategies 0 is an similar as a million.
2016-10-22 22:09:57 · answer #3 · answered by Anonymous · 0⤊ 0⤋