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Show that the functions in this interval have exactly one zero in the given interval,

~ This is inside the rolle's theorem, Mean Value Theorem section in calculus.

F(x)= x + (sin(x/3))^2 -8 on the interval (-infinity, infinity)

2007-10-23 15:59:38 · 1 answers · asked by whatsntomake 1 in Science & Mathematics Mathematics

1 answers

Hmm. Without doing the whole problem, I know where I'd start. sin(anything) is between -1 and 1. So sin^2 is between 0 and 1. I.e., x-8 <= F(x) <= x-7 everywhere.

So the only possible values of x for which there could be zeros lie in the interval [7,8]. Solve the problem there, and you'll have solved it overall.

2007-10-23 19:52:14 · answer #1 · answered by Curt Monash 7 · 0 0

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