When f(x)=4x^2+5x-3, evaluate f(-4)?

1 ⤊

2007-10-23 15:57:14 · 6 answers · asked by Trickster 1 in Science & Mathematics ➔ Mathematics

f(-4) = 64 - 20 - 3 = 41

2007-10-24 07:15:32 · answer #1 · answered by Como 7 · 0⤊ 0⤋

= 4*(-4)^2 + 5*(-4) - 3
= 4*16 - 20 -3
= 64 -23
= 41

2007-10-23 23:00:53 · answer #2 · answered by hemant_gome 2 · 0⤊ 0⤋

4(-4)^2+5(-4)-3

64-23=41

2007-10-23 23:00:43 · answer #3 · answered by Greg D 2 · 0⤊ 0⤋

4(-4)^2+5(-4)-3,
4(+16)-20-3
64-20-3
44-3
41

2007-10-23 23:01:00 · answer #4 · answered by a c 7 · 0⤊ 0⤋

that means substitute -4 for x

f(-4)=4(-4)^2+5(-4)-3
f(-4)=41

2007-10-23 23:00:33 · answer #5 · answered by Tim F 2 · 1⤊ 0⤋

f(x)=4x^2+5x-3
f(-4)=4(-4)^2+5(-4)-3
f(-4)=64-20-3
f(-4)=41

2007-10-23 23:00:52 · answer #6 · answered by ptolemy862000 4 · 0⤊ 0⤋