The average of four odd integers is 34. Find the integers.
I need to know the steps.
2007-10-23 15:11:34 · 5 answers · asked by apetkw 2 in Science & Mathematics ➔ Mathematics
(x + x + 2 + x + 4 + x + 6)/4 =34
4x + 12 = 34 x 4
4x + 12 = 136
4x = 124
x = 31
so 31, 33, 35, 37
2007-10-23 15:15:34 · answer #1 · answered by leo 6 · 4⤊ 0⤋
Assuming they're consecutive odd integers, let the smallest one be n. Then the others are n+2, n+4 and n+6.
So the average is (n + n+2 + n+4 + n+6) / 4 = (4n+12) / 4 = n+3. So n+3 = 34, i.e. n = 31.
So the integers are 31, 33, 35, 37.
2007-10-23 15:16:52 · answer #2 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
permit's take 3 even consecutive integers. permit the 1st one be x. which potential, because they're consecutive, here 2 integers would be x + 2 and x + 4 x, x + 2, x + 4 The sum of the small and larger of those is 20; that is x + (x + 4) = 20 resolve this. 2x + 4 = 20 2x = sixteen x = 8 So it follows the integers are 8, 10, 12. you're basically right.
2017-01-04 08:53:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x = 1st consecutive odd integer
x+2 = 2nd consecutive odd integer
x+4 = 3rd consecutive odd integer
x+6 = 4th consecutive odd integer
To find the average, add them up and divide by how many things you added, so
(x + x+2 + x+4 + x+6)/4 = 34
(4x + 12)/4 = 34
x + 3 = 34
x = 31
Then:
x+2 = 33
x+4 = 35
x+6 = 37
I hope this helps!
2007-10-23 15:17:10 · answer #4 · answered by math guy 6 · 0⤊ 0⤋
here:( x+x+2+x+4+x+6)/4=34
or 4x+12=34*4
or x=31
so other nos. are 33,35,37
2007-10-23 22:45:52 · answer #5 · answered by Sumita T 3 · 0⤊ 0⤋