English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Like in 2Na + Br2 ==> 2NaBr , which is oxidized and which is reduced?

2007-10-23 14:40:08 · 10 answers · asked by chrissymoo7 3 in Science & Mathematics Chemistry

10 answers

Sodium is oxidized as its oxidation state increases from 0 to +1 in NaBr. Whereas bromine is reduced as its oxidation state decreases from 0 to -1 in NaBr.

NaBr consists of Na+ ion and Br- ion
=> oxidation state of Na+ ion is +1 and oxidation state of Br- ion is -1

Na + Br ---both atoms have an oxidation state of 0

2007-10-23 14:45:42 · answer #1 · answered by ♪£yricảl♪ 4 · 0 0

The earliest view of oxidation and reduction is that of adding oxygen to form an oxide (oxidation) or removing oxygen (reduction). They always occur together. For example, in the burning of hydrogen 2H2 + O2 -> 2H2O the hydrogen is oxidized and the oxygen is reduced. The combination of nitrogen and oxygen which occurs at high temperatures follows the same pattern. N2 + O2 -> 2NO This formation of nitric oxide oxidizes the nitrogen and reduces the oxygen. In some reactions, the oxidation is most prominent. For example in the burning of methane, CH4 + 2O2 -> CO2 + 2H2O both carbon and hydrogen are oxidized (gain oxygen). The accompanying reduction of oxygen is perhaps easier to see when you describe reduction as the gaining of hydrogen.

2016-04-10 01:04:01 · answer #2 · answered by Anonymous · 0 0

the way to do these problems is consider reduction as a reduction in its oxidation state. So sodium and bromine in elemental form are 0 state now on the right side bromine has an oxidation state of -1, -1 is less then 0 so it must have been reduced

2007-10-23 14:48:19 · answer #3 · answered by Anonymous · 0 0

oxidation = loss of electrons
reduction = gain of electrons
Na going to Na+, loses an electron. Oxidation of the Na
Br2 going to 2Br-, gains electrons. Reduction of the Br2.

2007-10-23 14:43:33 · answer #4 · answered by papastolte 6 · 0 0

Look at the oxidation numbers: Na(O.N.=0) and Br2(O.N.=0) make NaBr where O.N. of Na is +1 and that of Br is -1.

Increase in O.N. = oxidation
Decrease in O.N. = reduction
So Na is oxidized whereas Br2 is reduced.

In terms of electron loss and gain: Na loses one electron from Na+ and Br gains one electron to form Br-. (Na+ and Br- forms the compound NaBr). Loss of electron = oxidiation (Na is oxidized), and gain of electron = reduction (Br is reduced).

2007-10-23 14:44:40 · answer #5 · answered by Dr. K 3 · 0 0

oxidized reactants increase ionization number and reduced reactants decrease ionization number. In your example, Na(0) is oxidized to Na(+1) and Br(0) is reduced to Br(-1).

2007-10-23 14:46:37 · answer #6 · answered by cattbarf 7 · 0 0

Who gain the electrons is reduction
Who loses the electrons is oxidation.

2007-10-23 14:42:39 · answer #7 · answered by lost_in_afantasy 2 · 0 0

the sodium is oxidized, because it has a positive charge as an ion, and the Br is reduced, since it has a negative charge as an ion.

2007-10-23 14:43:32 · answer #8 · answered by archerpro101 3 · 0 0

LEO GER
LEO= loses electrons oxidize
GER= gains electron reduced
sodium is oxidized
Br is oxidize

2007-10-23 14:42:40 · answer #9 · answered by Anonymous · 0 0

Here is a previous question to help you:
http://answers.yahoo.com/question/index;_ylt=As2.h9KdCyBP8IXUsDYtJGMjzKIX;_ylv=3?qid=20070430145909AA6xpuz

2007-10-23 14:45:19 · answer #10 · answered by Crazy and Lovin It 4 · 0 0

fedest.com, questions and answers