[07]
Peter has 5,John has 8 and Sam has 16
marbles
Let Peter have x narbles
Therefore,John has x+3 marbles,andSam has 2(x+3) 0r 2x+6 marbles
According to the problem
x+x+3+2x+6=29
4x+9=29
4x=29-9=20
x=20/4=5
Therefore Peter has 5 marbles
John has 5+3=8 marbles,and
Sam has 8*2 or 16 marbles
2007-10-23 13:39:21
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answer #1
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answered by alpha 7
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John = J
Peter = P
Sam = S
John has 3 more marbles than Peter.
J = P + 3 or J - 3 = P
Sam has twice as many marbles as John.
S = 2J
Together they have 29 marbles (? A bit vague so I'm assuming that John, Peter, and Sam have 29 marbles in total.)
S + P + J = 29
Now substitute the first two equations into the third equation.
2J (Which is equal to S) + [J - 3] (Which is equal to P) + J = 29.
Combine like terms: 4J - 3 = 29.
Add the three to both sides and divide each side by four.
You now know that John has 8 marbles.
Substitute the 8 into the second equation (S = 2J.) 2 X 8 = 16. Sam has 16 marbles. Substitute the 8 into the first equation (J = P + 3.) 8 = P + 3. Subtract the 3 from both sides and now you know that Peter has 5 marbles.
Does this check out? 5 + 8 + 16 = 29. Yes, it works.
Answers: Peter has 5 marbles. John has 8 marbles. Sam has 16 marbles.
2007-10-23 13:43:56
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answer #2
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answered by dcam90 3
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John has 8 marbles
Peter 5 marbles
Sam 16 marbles
2007-10-23 13:39:31
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answer #3
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answered by JazzyJeff 2
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Hello,
Let let p = Peter's marbles
so p+3 = John's
2(p+3) = Sam's
So we have p + p+3 + 2(p+3) = 4p + 9 = 29 so p = 5
p+3 = 8
2*8 = 16
5 + 8 + 16 = 29
Hope This Helps!!
2007-10-23 13:40:19
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answer #4
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answered by CipherMan 5
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Say Peter has P marbles
Then John has P+3 marbles
And Sam has 2(P+3) marbles
Now for the last sentence:
P + (P+3) + 2(P+3) = 29
Solve for P, you'll see P = 5, now work from there.
2007-10-23 13:40:05
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answer #5
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answered by TurtleFromQuebec 5
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Let us assume that john has x marbles.
Peter has y marbles.
Sam has z marbles.
x=y+3 -- (1)
z=2x -- (2)
x+y+z=29 --- (3)
from (1) y=x-3
from (2) z=2x
(3) becomes x+(x-3)+2x=29
4x-3=29
4x=32
x=8 (John has)
using (2) Sam has 8(2)=16 marbles
so, 29-16-8=5 marbles is what Peter has.
John = 8
Peter= 5
Sam = 16
2007-10-23 13:46:12
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answer #6
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answered by cidyah 7
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John: x + 3
Peter: x
Sam: 2(x+3)
x+3 + x + 2(x+3) = 29
x+3+x+2x+6 = 29
4x+9=29
4x=20
x=5
So,
John: 5 + 3 = 8
Peter: 5
Sam: 2(5+3) = 2(8) = 16
Check: 8 + 5 + 16 = 29?
Yes, hope that helps :)
2007-10-23 13:41:42
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answer #7
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answered by 1294 4
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j = 3 + p --------- p stands for peter.
p
s = 2( 3 + p )
so (3 + p) + p + 2( 3+p ) = 3 + 2p +6 + 2p = 29
9 + 4p = 29
4p = 20
divide boths sides by 4
peter has 5.
john has 8
sam has 16
2007-10-23 13:41:40
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answer #8
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answered by Jankitty 2
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