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8 answers

[07]
Peter has 5,John has 8 and Sam has 16
marbles
Let Peter have x narbles
Therefore,John has x+3 marbles,andSam has 2(x+3) 0r 2x+6 marbles
According to the problem
x+x+3+2x+6=29
4x+9=29
4x=29-9=20
x=20/4=5
Therefore Peter has 5 marbles
John has 5+3=8 marbles,and
Sam has 8*2 or 16 marbles

2007-10-23 13:39:21 · answer #1 · answered by alpha 7 · 0 1

John = J
Peter = P
Sam = S

John has 3 more marbles than Peter.

J = P + 3 or J - 3 = P

Sam has twice as many marbles as John.

S = 2J

Together they have 29 marbles (? A bit vague so I'm assuming that John, Peter, and Sam have 29 marbles in total.)

S + P + J = 29

Now substitute the first two equations into the third equation.

2J (Which is equal to S) + [J - 3] (Which is equal to P) + J = 29.

Combine like terms: 4J - 3 = 29.
Add the three to both sides and divide each side by four.
You now know that John has 8 marbles.

Substitute the 8 into the second equation (S = 2J.) 2 X 8 = 16. Sam has 16 marbles. Substitute the 8 into the first equation (J = P + 3.) 8 = P + 3. Subtract the 3 from both sides and now you know that Peter has 5 marbles.

Does this check out? 5 + 8 + 16 = 29. Yes, it works.

Answers: Peter has 5 marbles. John has 8 marbles. Sam has 16 marbles.

2007-10-23 13:43:56 · answer #2 · answered by dcam90 3 · 1 0

John has 8 marbles
Peter 5 marbles
Sam 16 marbles

2007-10-23 13:39:31 · answer #3 · answered by JazzyJeff 2 · 0 1

Hello,

Let let p = Peter's marbles

so p+3 = John's

2(p+3) = Sam's

So we have p + p+3 + 2(p+3) = 4p + 9 = 29 so p = 5

p+3 = 8

2*8 = 16
5 + 8 + 16 = 29

Hope This Helps!!

2007-10-23 13:40:19 · answer #4 · answered by CipherMan 5 · 2 0

Say Peter has P marbles
Then John has P+3 marbles
And Sam has 2(P+3) marbles

Now for the last sentence:
P + (P+3) + 2(P+3) = 29

Solve for P, you'll see P = 5, now work from there.

2007-10-23 13:40:05 · answer #5 · answered by TurtleFromQuebec 5 · 2 0

Let us assume that john has x marbles.
Peter has y marbles.
Sam has z marbles.
x=y+3 -- (1)
z=2x -- (2)
x+y+z=29 --- (3)
from (1) y=x-3
from (2) z=2x
(3) becomes x+(x-3)+2x=29
4x-3=29
4x=32
x=8 (John has)
using (2) Sam has 8(2)=16 marbles
so, 29-16-8=5 marbles is what Peter has.
John = 8
Peter= 5
Sam = 16

2007-10-23 13:46:12 · answer #6 · answered by cidyah 7 · 1 0

John: x + 3
Peter: x
Sam: 2(x+3)

x+3 + x + 2(x+3) = 29
x+3+x+2x+6 = 29
4x+9=29
4x=20
x=5
So,
John: 5 + 3 = 8
Peter: 5
Sam: 2(5+3) = 2(8) = 16
Check: 8 + 5 + 16 = 29?
Yes, hope that helps :)

2007-10-23 13:41:42 · answer #7 · answered by 1294 4 · 1 0

j = 3 + p --------- p stands for peter.
p
s = 2( 3 + p )

so (3 + p) + p + 2( 3+p ) = 3 + 2p +6 + 2p = 29
9 + 4p = 29
4p = 20

divide boths sides by 4
peter has 5.
john has 8
sam has 16

2007-10-23 13:41:40 · answer #8 · answered by Jankitty 2 · 1 0

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