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Consider the following data.

N2(g) + O2(g) 2 NO(g) H = +180.7 kJ
2 NO(g) + O2(g) 2 NO2(g) H = -113.1 kJ
2 N2O(g) 2 N2(g) + O2(g) H = -163.2 kJ

Use Hess's law to calculate H for the reaction below.

N2(g) + 2 O2(g) 2 NO2(g)
H = ____ kJ

2007-10-23 13:04:00 · 2 answers · asked by Circuiteer 1 in Science & Mathematics Chemistry

2 answers

N2(g) + O2(g) ==> 2 NO(g) H = +180.7 kJ........(1)
2 NO(g) + O2(g) ==> 2 NO2(g) H = -113.1 kJ...(2)
2 N2O(g) ==> 2 N2(g) + O2(g) H = -163.2 kJ....(3)

(1) + (2)
N2(g) + 2 O2(g) ==> 2 NO2(g)
H = _67.6_ kJ

2007-10-24 13:08:47 · answer #1 · answered by Hahaha 7 · 0 0

least complicated wy to to it is the locate the values of the enthalpy's of formation of the compounds contained in the equation then used, products minus reactants, or you need to do an similar with a thermodynamic cycle even though it truly is slightly more suitable complicated.

2016-10-22 21:58:11 · answer #2 · answered by Anonymous · 0 0

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