Solve:
cscx+2cotx=0
2007-10-23 12:41:24 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Man, I'm In Pre-Algebra!
2007-10-23 12:44:08 · answer #1 · answered by Anonymous · 0⤊ 2⤋
Hello,
We have 1/sinx +2/tanx = 0 using a common denominator of sinx * tanx we have (tanx +2 sinx)/(sinx*tanx) = 0 now mul both sides by sinx*tanx and we obtain tanx + 2sinx = 0
but tanx = sinx/cosx giving us sinx/cosx + 2sinx = 0 use the common denominator of cosx we get (sinx+2sinx*cosx)/cosx = 0 and then sinx + 2sinx*cosx = 0 factor out sinx giving us
sinx(1 + 2cosx) = 0 so sinx = 0 and 1 +2 cosx = 0 so
sinx = 0 and cosx = -1/2 Sinx = 0 at 0, 180, 360 and cosx = -1/2 at a reference 30 degrees in the 3rd and 4th quadrants.
Well let you finish.
Be sure that you check your answers in the original equation!!
Hope This Helps!
2007-10-23 13:07:09 · answer #2 · answered by CipherMan 5 · 0⤊ 0⤋
cscx+2cotx = 0
1/sinx+2cosx/sinx = 0
(1 + 2cosx)/sinx = 0
Multiply both sides by sinx
1 + 2cosx = 0
2cosx = -1
cosx = -1/2
x = 120°
.
2007-10-23 12:49:34 · answer #3 · answered by Robert L 7 · 0⤊ 0⤋
csc x + 2 cotx = 0
1/sinx + 2 cosx/sinx = 0
multiply with sinx
1 + 2 cosx = 0
2cosx = -1
cosx = -1/2
x = pi -pi/3 = 2 pi/3, 4pi/3
2007-10-23 12:53:52 · answer #4 · answered by mohanrao d 7 · 0⤊ 0⤋