English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

What is the average force exerted by a shot-putter on a 7.0-kg shot if the shot is moved through a distance of 2.8m and is release with a speed of 13 m/s?

2007-10-23 11:34:46 · 2 answers · asked by kelvinlam48 2 in Education & Reference Homework Help

2 answers

If F is the average force, then:
(2.8m) * F = (7.0kg)(13m/s)^2 / 2
F = (7 * 13^2) / (2 * 2.8)
= 211.25 N.

2007-10-28 22:41:05 · answer #1 · answered by Anonymous · 0 0

Above answer looks good!

2007-10-31 11:09:07 · answer #2 · answered by jemhasb 7 · 0 0

fedest.com, questions and answers