In the diagram of the right triangle ABC, CD is drawn perpendicular to hypotenuse AB. If AB = 16 and DB = 4, find BC. Please help!!!
http://jwilson.coe.uga.edu/EMT668/EMAT6680.2000/Obara/Math%207200/Homework%20%202%20Math%207200%20folder/image22.gif
The picture looks like that, only the sides arn't labled, and we arn't looking for the x on the diagram.
2007-10-23 11:30:05 · 11 answers · asked by Fuzzyglasses 3 in Education & Reference ➔ Homework Help
sorry guys, but thats all the info I have!! My teacher is such a butt!!
2007-10-23 13:29:21 · update #1
since we are working with right triangle you can use the
pythagorean theorem:
a^2 + b^2 = c^2
a is the short leg
b is the longer leg
c is the hypotenuse
In this case AB is the hypotenuse and
DB seems like the short leg
so:
4^2 + b^2 = 16^2
16 + b^2 = 256
b^2 = 256 - 16
b^2 = 240 ( square root both sides)
b = 15.49 or the square root of 240
2007-10-23 11:41:00 · answer #1 · answered by Caesar 3 · 0⤊ 1⤋
A guy at my school knows. If no one has responded by then, I will ask and post the answer here.
2007-10-23 18:40:59 · answer #2 · answered by Anonymous · 0⤊ 0⤋
thats not the same triangle.seperate ACD and BCD [with CD the seperator] , but remember ACD =BCD
AD=8
CD=4
AC=8.94[find with pythagorean theory]
BC=AC
AC=8.94
2007-10-23 19:00:31 · answer #3 · answered by Torie 2 · 0⤊ 0⤋
Hmm...Are you sure you didnt forget to write something else? ..'Cause with the info you wrote, can't solve it :)
Check again your post , I'll check later =)
2007-10-23 18:42:13 · answer #4 · answered by Ruk1a_ 1 · 0⤊ 0⤋
I think that you might be missing some information that you need to solve it
2007-10-23 18:38:01 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I don't know..................
I tried, but i think you need more info.
Unless, there is a rule that CD has to be 4 also.
I'll be watching.
2007-10-23 18:36:51 · answer #6 · answered by gallopinto 2 · 0⤊ 0⤋
i don't think you can do this question unless the triangle CBD is isosceles or the question gives you another clue
2007-10-23 18:43:31 · answer #7 · answered by Imclc 2 · 0⤊ 0⤋
ac^2+bc^2=256
ad^2+cd^2=ac^2
ac2-bc^2=128
therefore bc=8*sqrt(3).
2007-10-23 18:42:09 · answer #8 · answered by Anonymous · 0⤊ 0⤋
A2+B2=C2 omg it is sooooo ez
2007-10-23 18:34:20 · answer #9 · answered by Steph 2 · 0⤊ 1⤋
sorry we just learned this and i would love to help but i didnt do so good on that test
2007-10-23 18:36:11 · answer #10 · answered by ladyrose939393 2 · 0⤊ 1⤋