2007-10-23 10:33:01 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
7r + 49 = 5r + 59
7r - 5r = 59 - 49
2r = 10
r = 5
2007-10-23 10:37:10 · answer #1 · answered by Como 7 · 1⤊ 0⤋
distribute the 7:
7(r) + 7(7) = 5r +59
7r + 49 = 5r + 59
Subtract 49 from both sides:
7r + 49 -49 = 5r + 59 -49
7r = 5r +10
Subtract 5r from both sides:
7r-5r = 5r-5r +10
2r = 10
Now divide by 2:
2/2*r = 10/2
r = 5
Check:
7(5+7)= 7(12) = 84
5(5)+59 = 25 + 59 = 84
Since 84 = 84, r = 5.
2007-10-23 10:37:56 · answer #2 · answered by sayamiam 6 · 0⤊ 1⤋
7(r + 7) = 5r + 59 distribute the 7
7r+49=5r+59 subtract 5r
2r+49=59 subtract 49
2r=10 divide by 2
r=5
:) Good luck!
2007-10-23 10:47:18 · answer #3 · answered by Anonymous · 0⤊ 1⤋
7r+49=5r+59 distribute 7
2r+49=59 subtract 5r
2r=10 subtract 49
r=5 divide by 2
2007-10-23 10:36:12 · answer #4 · answered by Anonymous · 0⤊ 0⤋
7(r+7)=5r+59
7r + 49 = 5r + 59
2r = 10
r = 5
2007-10-23 10:36:12 · answer #5 · answered by aaron.brake 3 · 1⤊ 0⤋
7r + 49 = 5r + 59
Subtract 5r from both sides and subtract 29 from both sides
2r = 10
Divide by 2
r = 5
2007-10-23 10:35:16 · answer #6 · answered by Ms. Exxclusive 5 · 0⤊ 0⤋
7(r+7)=5r+59
7r+49=5r+59
2r=10
r=5
2007-10-23 10:36:44 · answer #7 · answered by Willy P 2 · 0⤊ 0⤋
7xR,7x7 makes 7r+49=5r+59
-49 -49
7r=5r+10
-5r -5r
2r=10
divided by2 (2r and 10)
r=5
2007-10-23 10:38:13 · answer #8 · answered by Anonymous · 0⤊ 1⤋
7(r+7)=5r+59
7r+49=5r+59
7r-5r=59-49
2r=10
r=5
2007-10-23 12:04:08 · answer #9 · answered by ♥♥felisha♥♥ 5 · 0⤊ 1⤋
7x7r=7r and 7x7=49
7r+49=5r+59
7r=59-49+5r
7r=10+5r
7r-5r=10
2r=10
r=5
2007-10-23 10:39:28 · answer #10 · answered by jxt299 7 · 0⤊ 1⤋