Newtons second law of motion:
Observed from an inertial reference frame, the net force on a particle is proportional to the time rate of change of its linear momentum F = d[mv] / dt or most common: F = ma
2007-10-23 09:54:26
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answer #1
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answered by Anonymous
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OK, without math. Push as hard as you can again a wall. What happens? Nothing (maybe your arms get tired), the wall stands there and pushes back against your hands. But it doesn't move and you, steadfast to the very end, don't move either.
All that force (the pushing) and neither moves. Why is that?
Well, that's because the wall is pushing back on your hand as hard as you are pushing on that wall. But, and this is a big BUT, it's pushing in your direction while you are pushing in its direction. Thus, we have equal pushes (forces) in magnitude, but in opposite directions.
And when that happens, the forces are said to be equal but opposite forces and, this is a big point, they cancel each other out. In other words, there is zero NET force acting on you and on the wall. Thus, there is nothing to make you or the wall move. So there you are, two masses (you and the wall) being pushed on by equal and opposite forces and neither one of those masses is moving.
Now, let's say you are Mr. S, who can leap tall buildings in a single bound and who is more powerful than a locomotive. You push on the wall and it pushes back. So you push harder and it pushes harder back. But then, the wall can do no more and it breaks as you push. What happens?
The wall starts to move, accelerate backwards away from your push. And, this is important, the reason the wall accelerates now is because it cannot push back with equal and opposite force to your superhuman push. The net force acting on the wall is no longer zero because your push is greater than what the wall can push back with. There is now a net positive force greater than zero pushing (accelerating) the wall backwards.
And there you have it...without math. Acceleration occurs on a mass (like the wall) when there is a net non-zero force acting on it. And, as you might surmise, greater net force gives us greater acceleration. In fact, we can say the acceleration is proportional to the net force applied to the mass.
2007-10-23 10:10:21
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answer #3
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answered by oldprof 7
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acceleration =force divided by mass
If force increases acceleration increases
If mass increases acceleration decreases
2007-10-23 09:56:27
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answer #4
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answered by andyg77 7
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Acceleration as function of time is rate of change of Velocity with respect to time:
a(t) = dv(t)/dt = d^2 x(t)/dt^2
Force: F = ma (Newton's 2nd Law (with m = constant or function of time))
F(t) = m a(t)
2007-10-23 09:58:16
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answer #5
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answered by Richard H 2
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