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Prove the identity: The lower bound is "s" ∫ ∫ (a dot n) dS = 0, where a is a constant vector and assuming that "s" satisfys the conditions of the Divergence Theorem

2007-10-23 09:35:21 · 1 answers · asked by Madd_ox 2 in Science & Mathematics Mathematics

1 answers

As you know, the Divergence Theorem says

∫ ∫ (a dot n) dS = ∫ ∫ ∫ div a dV

where the triple integral is over the volume enclosed by the surface s. The divergence of a constant vector is zero, right?

2007-10-24 06:36:09 · answer #1 · answered by Ron W 7 · 0 0

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