2007-10-23 09:07:17 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
just divide 32 by avagadro's number.
2007-10-23 09:09:54 · answer #1 · answered by Troy 6 · 0⤊ 0⤋
32
2007-10-23 09:10:15 · answer #2 · answered by Thomas E 6 · 0⤊ 0⤋
The Avogadro constant is the number of "atoms" in this case , present in one mole of the element in question. 1 mole of sulfur weighs 32g The Avogadro constant is 6.022 x 10^23 meaning there are 6.022 x 10^23 atoms in 32g of sulfur. So one atom would weigh 32 / (6.022 x 10^23) g
2016-05-25 05:09:51 · answer #3 · answered by ? 3 · 0⤊ 0⤋
Serious? 32 grams.
2007-10-23 09:10:06 · answer #4 · answered by Madolyn 2 · 0⤊ 0⤋
32/6.022 x 10^23 = 5.31 x 10^-23 g
NB 6.022 x 10^23 is the Avogadro Constant; it is the number of atoms in one mole
2007-10-23 09:12:24 · answer #5 · answered by lenpol7 7 · 0⤊ 0⤋
divide from Avogadro constant: answer is 5,3156146E-23
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you can check that:
Proton mass is 1,672E-27 kg
Neutron mass is 1,675E-27 kg
Electron mass is 9,11E-31 kg
so sulfur-32 mass in grams is 5,3566576E-23
2007-10-23 09:27:49 · answer #6 · answered by Anonymous · 1⤊ 0⤋
16 * 0,007277u+16*0.008665u+16*0.000548u
with u=1.6602*10^-24
=> 4.38*10^-25 g
2007-10-23 09:13:59 · answer #7 · answered by bertyhell 3 · 0⤊ 1⤋