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A potter's wheel with a moment of inertia of 8.0 kg.m^2 has 5.0 N.m applied to it. If it starts from rest, calculate (a) the wheel's angular velocity and (b) it's kinetic energy 10.0s later.

2007-10-23 08:52:15 · 1 answers · asked by Gary 2 in Science & Mathematics Physics

1 answers

T=I A
T -torque
I moment of inertia
A = angular acceleration

also T=r x F

A= T/I
angular velocity omega = At + initial omega ( initial omega=0)
so
omega= (T/I)t
omega= (r x F/I)t
where r is the radius or distance from the center of the potter wheel's to the point where force was applied. r- is not given.

and

2. Kinetic energy
Ke= (1/2) I omega^2

2007-10-23 09:00:14 · answer #1 · answered by Edward 7 · 1 0

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