Solve 3x + 2 >14
2007-10-23 08:45:38 · 9 answers · asked by brownk_1999 1 in Science & Mathematics ➔ Mathematics
3x > 14-2
3x > 12
x > 4
2007-10-23 08:59:11 · answer #1 · answered by jewel7962002 1 · 0⤊ 0⤋
X=5
2007-10-23 09:00:16 · answer #2 · answered by unknownpheonix360 2 · 0⤊ 0⤋
3x+2>14
collect like terms therefore
3x > 14 -2 (you bring 2 over so it becomes negative.)
3x > 12
now you are going to get rid of the three, bcus you want x by itself.
3x /3 > 12 /3
cancel. example. three into three= 1 and three into twelve = 4
therefore
answer x= 4
2007-10-23 09:00:22 · answer #3 · answered by Lexie 3 · 0⤊ 0⤋
3x > 14-2
3x > 12 divide by 3
x > 4
2007-10-23 08:48:37 · answer #4 · answered by Linda K 5 · 0⤊ 0⤋
Subtract the 2 from both sides.
3x > 12
Divide each side by 3 and your final answer should be x > 4.
This means that any x value greater than four will satisfy the equation.
2007-10-23 08:49:15 · answer #5 · answered by dcam90 3 · 0⤊ 0⤋
3x + 2 >14
- 2 -2
3x > 12
divide each side by 3
x>4
always remember to get rid of normal numbers before you get rid of numbers with variables
2007-10-23 09:09:36 · answer #6 · answered by Anonymous · 0⤊ 0⤋
3x+2>14
Subtract 2 from both sides
3x+2-2>14-2
Tidy up
3x>12
Divide both sides by 3
3x/3>12/3
Tidy up
x>4
2007-10-23 08:50:32 · answer #7 · answered by Grampedo 7 · 0⤊ 0⤋
3x + 2 >14
3x > 12, after subtracting 2 from both sides
3x > 12
x > 4, after dividing both sides by 3
2007-10-23 08:49:11 · answer #8 · answered by 1294 4 · 0⤊ 0⤋
3x > 12
x > 4
2007-10-24 06:55:31 · answer #9 · answered by Como 7 · 0⤊ 0⤋