A=h(b1+b2)/2;for b
Please be pretty sure before you submit your answer!
2007-10-23 08:17:58 · 11 answers · asked by yo mama 1 in Science & Mathematics ➔ Mathematics
A smart person like sahsjing would jus give me two answers. One with b1 and one with b2. Thats what I meant. Solve for both. Sorry I wasn't too clear. I'l try better next time. Thanks a lot!
2007-10-23 08:32:24 · update #1
b1 = (2A/h) - b2
b2 = (2A/h) - b1
2007-10-23 08:20:49 · answer #1 · answered by sahsjing 7 · 1⤊ 0⤋
This is an equation to find the area of a trapezoid. Are you looking for b1 or b2? h is the height, (distance between the two bases), b1 and b2 are the lengths of the bases (they are the lines that are parallel to each other). You can solve for b1 or b2 in terms of the other base, area, and height. But I'm confused what you are looking for.
2007-10-23 15:22:27 · answer #2 · answered by gang$tahtooth 5 · 1⤊ 0⤋
That's a formula for the area of a trapezoid, there is nothing to solve. b1 and b2 are the two different bases that you plug in to get the area.
2007-10-23 15:21:57 · answer #3 · answered by suspendedagain300 6 · 1⤊ 0⤋
A = (h.b1 +h.b2)/2
you have two values for b and no true b identity, therefore you cannot solve for b, instead you will be solving for the average of b1 and b2 which is (b1+b2)/2
therefore;
A = h(b1 +b2)/2
A/h = Average of B
2007-10-23 15:21:54 · answer #4 · answered by David F 5 · 0⤊ 0⤋
What "b"? You have a b1 and a b2, but no "b".
2007-10-23 15:20:14 · answer #5 · answered by Anonymous · 0⤊ 0⤋
only thing I can see is multiplying it out
A=H(b1 + b2) / 2
A= Hb1 + Hb2 / 2
2007-10-23 15:24:35 · answer #6 · answered by Earth the Poet 3 · 0⤊ 0⤋
As you can see from the previous responses, your question makes no sense as you posted it. So I will offer you some of your own advice. When posting a question, please be pretty sure you know what the question is before you post it.
2007-10-23 15:25:58 · answer #7 · answered by Michael M 7 · 0⤊ 0⤋
Makes no sense to me;-{ check your question source.
2007-10-23 15:21:14 · answer #8 · answered by Robert S 7 · 0⤊ 1⤋
No i can not solve that its soo hard.
Good Luck with it!!
2007-10-23 15:20:55 · answer #9 · answered by Swimmy101 2 · 0⤊ 1⤋
Do your own h/w
2007-10-23 15:20:46 · answer #10 · answered by Grumble 4 · 0⤊ 1⤋