One circle has a center (0,4) and a radius of 5 the other has a center (0,-5) and a radius of 7. The x coordinates of the points of intersection of the two circles are.
(x1,x2)
2007-10-23 07:29:07 · 3 answers · asked by ws 3 in Science & Mathematics ➔ Mathematics
Circle 1
x² + (y - 4)² = 25
x² + y² - 8y + 16 = 25
x² + y² - 8y = 9
Circle 2
x² + (y + 5)² = 49
x² + y² + 10y + 25 = 49
x² + y² + 10y = 24
9 + 8y = 24 - 10y
18y = 15
y = 5/6
x² + (5/6)² + 50/6 = 24
x² + 25/36 + 300/36 = 24
x² + 325/36 = 24
x² = 864/36 - 325/36
x² = 539/36
x = ±√(539) / 6
2007-10-29 20:14:00 · answer #1 · answered by Como 7 · 1⤊ 0⤋
x² + (y-4)² = 25
x² + (y+5)² = 49
(y+5)² - (y-4)² = 24
(y²+10y+25) - (y²-8y+16) = 24
18y+9 = 24
18y = 15
y = 5/6
x² + (5/6-4)^2 = 25
x² + (19/6)^2 = 25
x² = 25 - 361/36 = 539/36
x = +-sqrt(539)/6
2007-10-23 07:57:19 · answer #2 · answered by np_rt 4 · 0⤊ 0⤋
You cannot expect to learn anything if you do not do your own homework.
2007-10-23 07:37:12 · answer #3 · answered by Greg H 4 · 0⤊ 1⤋