The center of gravity of the car is between the front and rear tires, and the horizontal distance between the center of gravity and the front axle is 1.02 m.
(a) Determine the normal force that the ground applies to each of the two front wheels
(b) Determine the normal force that the ground applies to each of the two rear wheels.
2007-10-23 07:15:55 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Use the fact that in equlibrium the sum of torques is equal to 0.
(a) Consider rear wheels as a pivot point. Then m*g*(2.5 - 1.02) = 2*Ff*2.5, so Ff = 1000*9.8*1.48/5 = 2900 N
(b) Consider front wheels as a pivot point. Then m*g*1.02 = 2*Fr*2.5, so Fr = 1000*9.8*1.02/5 = 2000 N
2007-10-23 07:22:45 · answer #1 · answered by Alexey V 5 · 3⤊ 1⤋
Sorry, I accidentally gave alexis a thumbs down. My trigger finder twitched before I got mouse in position. His answer is good.
2007-10-23 09:41:59 · answer #2 · answered by sojsail 7 · 1⤊ 0⤋