Lance and Mario were working in the snack bar at the turbulent tunas concert. they sold hot dogs for $1.65, hamburgers for $2.35, sodas for $0.85 and the combo plate for $3.89. They sold 80 items in an hour for $163.24. How many of each kind of food did they sell? and how much did they make on each kind of food?
Thanx a million! plzzzz show all work!
any help is appreciated! plz help me! what goes around comes around!
2007-10-23 06:20:14 · 3 answers · asked by mathewL 3 in Science & Mathematics ➔ Mathematics
D = 1.65
H = 2.35
S = .85
C = 3.89
They sold xDogs +yHamburgers +aSodas +bCombos
x +y +a+b = 80 OR 204.05(x + y + a + b) = 16324
x1.65 +y2.35 +a*.85 +b3.89 = 163.24
165x +235y +85a +389b = 16324
165(80-y-a-b) +235y +85a +389b = 16324
1200 -165y -165a -165b +235y +85a +389b = 16324
15124 = 70y -80a +224b
165x +235y +85a +389b = 204.05x + 204.05y + 204.05a + 204.05b
184.95b + 30.95y - 119.05a = 39.05x
x = (184.95b + 30.95y - 119.05a) / 39.05
165[(184.95b + 30.95y - 119.05a) / 39.05] +235y +85a +389b = 16324
... i think you can see where i am going with this... but it is way long and something you should be doing yourself.
Hope this direction helps you.
HINT for the end, everything ends in a multiple of 5c except the combo plate with is 3.89 ... use that to figure the resultant 163.24 total. It is key to solving this with this very "given" facts
2007-10-23 06:29:23 · answer #1 · answered by David F 5 · 0⤊ 0⤋
A As the sum end in decimal 9 and the the sum of the three first item ends in 5 or 0
3.89*combo must end in decimal nine so combo=1 , 11,21 or 31
Let´s start with 31
1.65 d+2.35 h +0.85 s=42.65
d+h+s=49
s= 49-d-h
1.65d +2.35 h +41.65 -085d-0.85h = 40.65
can´t be
combos =21
1.65 d +2.35h +0.85 s= 81.55
s= 59-d-h
8d+15 h = 314which gives as one of the solutions (there are more)
hot dogs 28
hamburger 6
sodas 25 and combos 21
also
hot dogs 13
hamburger 14 ,sodas 32
combos 21
There are many more solutions
2007-10-23 14:36:09 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
You have two equations for four unknowns. Surely you must have more information than this, unless you are expected to use trial and error?
2007-10-23 13:25:30 · answer #3 · answered by DWRead 7 · 0⤊ 0⤋