-♥-Help me solve this please?

Question

On a road trip, five friends drove at 50 miles per hour to California. On the way home, they took the same route but drove 75 miles per hour. How many miles did they drive on the way to California if the round trip took 10 hours?


don't give me the answer, just the steps.
thanks!

Answer 1

The formula to use is Rate x Time = Distance. I would use a chart:

direction | Rate | Time | Distance
----------------------------------------------------------
Going | 50 | x | 50x
----------------------------------------------------------
coming | 75 | 10 - x | 750 - 75x


Since it is a round trip, set the distances equal and solve for x. This is the time. Then multiply by 50 to get the distance.




The answers given above aren't correct... it should be:


300 miles.

Answer 2

On the way home, they moved faster than the road trip.
s is the distance from their home to Cali.
The time of:
- the road trip = s/50
- the way home = s/75
=> total driving time =s/50+s/75= 10
=> 3s/150+2s/150=10
=> 5s=1500
=> s=300 (miles)

Answer 3

Always set the unknown to be found, first.
Let M be the distance travelled one way.
Distance divided by speed equals time.
e.g. 1000 miles at 50 mph takes 20 hours.
We know that both ways took 10 hours.
So: M/50 + M/75 = 10

Answer 4

The distances traveles going and returning are equal so we can set

distance going = distance returning

Since distance equals rate x time we can let x be time going and since total time was 10 hours 10 - x is time returning. Therefore in our distance equation above we can write, using d = rt

50x = 75(10-x) which you can solve to get

x = 6 hrs going and 10-x = 4 hours returning.

Answer 5

Let X miles be the one way distance,

total time =10 hours

therefore 10=x/50+x/75;

solving it you get, x=300miles. This the the one way distance.

Answer 6

so lets say it takes x hrs to reach there..

so the distance on the way

50x

lets say it takes y hrs to come back
so distance coming back is 75y

now x+y = 10
50x = 75 y

or x=10-y
or 50(10-y)=75y
or 500 -50y = 75y
or 500 =125y
or y =4 x = 6
so it is 50X6 =300 miles on the way to california

Answer 7

Let Distance Be X
Time to go there is Y
So time to come back is 10 - Y
Speed = Dist./Time

case 1
=>50 = X/Y =>X = 50Y (Equation 1)
case 2
=>70 = X/10-Y (equation 2)
Substituting 1 in 2
70 = 50Y/10-Y
700-70Y=50Y
700=120Y
Y=35/6
Y=5.8Hours (apx.)
X=50Y = 290Miles
Y= Time taken to come back is 10 - 5.8 = 4.2 (apx.)

Answer 8

Let the hours going out = t1 and the hours coming back =t2.
Together, t1 + t2 = 10 hours.

Obviously, 50*t1 = 75*t2.

Solve for t1 or t2.

Answer 9

the same miles that you drove to get back.
the miles don't change is the time that changes because you were coming back faster.
i don't know where you got this ? but it doesn't make sence