American and I have a half sister whose father is from Sudan (arabic speaking, East Indian similar facial feature but Sudan is in Africa) does that make me a African-American by association?
2007-10-23 04:31:13 · 7 answers · asked by Anonymous in Society & Culture ➔ Cultures & Groups ➔ Other - Cultures & Groups
So then why do people think I'm a Black American? Our mother is Brazilian. Maybe since she's dark skinned they just assume this?
2007-10-23 04:43:12 · update #1
So according to what Mr318 is saying, I am a Black American? I guess maybe I can say I'm an African American too then?
2007-10-23 07:22:04 · update #2
So then a lot of Caucasians in the US should say that they are Black/African American as well, am I correct?
2007-10-23 08:07:11 · update #3
I'm not sure what that means, but it does sound like you're pretty to look at :-)
2007-10-23 09:14:44 · answer #1 · answered by inquiring black beauty 3 · 2⤊ 2⤋
In response to the last part of your question...
Brazilian isn't a race, but an ethnic group. In fact, there are more Brazilians with black blood than Americans (percentage-wise).
I knew a guy from Brazil who said he wasn't black back in college. He looked like Kevin Garnett, the NBA player but shorter.
I was like 'WTF'? But then again, many minorities in the U.S. push their 'ethnic' group first above race. Hey, it's their right.
Brazil had a history with the trans-Atlantic slave trade like the U.S. and it shows if you ever visit the country.
2007-10-23 11:52:22 · answer #2 · answered by Popsqually 6 · 1⤊ 0⤋
What country records your birth certificate ?
2007-10-23 14:27:10 · answer #3 · answered by Anonymous · 1⤊ 0⤋
No.
You can't claim your half brother and sister's parent's ethnicity.
2007-10-23 11:34:22 · answer #4 · answered by Anonymous · 5⤊ 0⤋
I don't think so, is one of your biological parents black, if not then no
2007-10-23 11:42:19 · answer #5 · answered by ? 5 · 1⤊ 0⤋
Nope, sorry.
2007-10-23 11:36:57 · answer #6 · answered by rachel m 4 · 2⤊ 0⤋
No. 2D
2007-10-23 11:50:00 · answer #7 · answered by 2D 7 · 0⤊ 0⤋