2007-10-23 03:28:21 · 4 answers · asked by Benjamin R 1 in Science & Mathematics ➔ Mathematics
Let the first integer be x
The next integer will be (x+1)
2x + 7(x+1) = 88
2x + 7x + 7 = 88
9x = 81
x = 9
x+1 = 10
The integers are 9 and 10
Check:
2*9 + 7*10
= 18 + 70
= 88
2007-10-23 03:32:23 · answer #1 · answered by gudspeling 7 · 1⤊ 0⤋
Let the first integer be x
The next integer will be (x+1)
2x + 7(x+1) = 88
2x + 7x + 7 = 88
9x = 81
x = 9 first integer and
x+1 = 10 second integer
2007-10-23 03:46:10 · answer #2 · answered by Pranil 7 · 0⤊ 0⤋
Let x and x+1 be the two consecutive integers.
2x+7(x+1)=88
2x+7x+7=88
9x+7=88
9x=81
x=9
9 and 10 are the integers.
2007-10-23 04:08:06 · answer #3 · answered by cidyah 7 · 0⤊ 0⤋
Let n be the first integer
Let n+1 be the second integer
2n + 7(n+1) = 88
2n + 7n + 7 = 88
9n = 88 - 7
9n = 81
n = 9
The numbers are 9 and 10.
As a double check:
2(9) + 7(10) =? 88
18 + 70 =? 88
88 = 88 <-- check
So the answer is the integers 9 and 10.
2007-10-23 03:33:12 · answer #4 · answered by Puzzling 7 · 2⤊ 0⤋